Question

A rectangle iron block of mass 10 kg is placed on the top of a table. Find the pressure exerted by the block on the table when 20 cm X 10 cm dimensions lie? Take g= 10 m/s²

Answer 1

Step 1: Given data,

Mass of block = $10kg$

Dimensions of block =$20cm\times 10cm$

Acceleration due to gravity = $10m/s^2$

Step 2:

Area of block =$20\times 10=200c{m}^2$

We know that $1cm={10}^{-2}m$

$200c{m}^2=200\times {\left({10}^{-2}\right)}^2{m}^2=200\times {10}^{-4}{m}^2=0.02m^2$

Step 3: Formula

Pressure=$\frac{Thrust\left(Force\right)}{Area}$

Step 4:

$$\begin{gathered} Force=mass\times accelerationduetogravity \\ Force=10\times 10=100N \end{gathered}$$

$Pressure=\frac{100}{0.02}=5000pa$

Hence, the pressure exerted on the table is $5000pa$