A rectangle is (8x + 5) cm long and (5x + 3) cm broad. Find its area.

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Solution

Length of the rectangle = (8x + 5) cm
Breadth of the rectangle = (5x + 3) cm
Area of rectangle = length × breadth
= (8x + 5)(5x + 3)
= 8x(5x + 3) + 5(5x + 3)
= 8x × 5x + 8x × 3 + 5 × 5x + 5 × 3
= 40x² + 24x + 25x + 15
= 40x² + 49x + 15
So, area of rectangle is (40x² + 49x + 15) cm².

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A rectangle is (8x + 5) cm long and (5x + 3) cm broad. Find its area.

Length of the rectangle = (8x + 5) cm Breadth of the rectangle = (5x + 3) cm Area of rectangle = length × breadth = (8x + 5)(5x + 3) = 8x(5x + 3) + 5(5x + 3) = 8x × 5x + 8x × 3 + 5 × 5x + 5 × 3 = 40x2 + 24x + 25x + 15 = 40x2 + 49x + 15 So, area of rectangle is (40x2 + 49x + 15) cm2.

Length of the rectangle = (8x + 5) cm
Breadth of the rectangle = (5x + 3) cm
Area of rectangle = length × breadth
= (8x + 5)(5x + 3)
= 8x(5x + 3) + 5(5x + 3)
= 8x × 5x + 8x × 3 + 5 × 5x + 5 × 3
= 40x² + 24x + 25x + 15
= 40x² + 49x + 15
So, area of rectangle is (40x² + 49x + 15) cm².