A rectangle of length $24 c m$ and breadth $17 c m$ or A square of side $21 c m$ . The difference between the area of rectangle and square ( in $c m^{2}$ )

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Solution

Area of the rectangle with length $24$ cm and breadth $17$ cm $= 24 \times 17 = 408 ‬$ sq.cm
Area of the square of side $21$ cm $= 21^{2} = 441$ sq.cm
$∴$ Area of the square $>$ Area of the rectangle
difference of area=441-408=33sq.cm

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A rectangle of length 24 cm and breadth 17 cm or A square of side 21 cm. The difference between the area of rectangle and square ( in cm2)

Area of the rectangle with length 24cm and breadth 17cm=24×17=408‬sq.cmArea of the square of side 21cm =212=441sq.cm∴ Area of the square>Area of the rectangledifference of area=441-408=33sq.cm

A rectangle of length $24 c m$ and breadth $17 c m$ or A square of side $21 c m$ . The difference between the area of rectangle and square ( in $c m^{2}$ )

Area of the rectangle with length $24$ cm and breadth $17$ cm $= 24 \times 17 = 408 ‬$ sq.cm
Area of the square of side $21$ cm $= 21^{2} = 441$ sq.cm
$∴$ Area of the square $>$ Area of the rectangle
difference of area=441-408=33sq.cm