A rectangle plot of land measures 45 m ×30 m. A boundary wall of height 2.4 m is built all round the plot at a distance of 1 m from the plot. Find the area of the inner surface of the boundary wall.
A
226.2m2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
457.2m2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
379.2m2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
291.2m2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C379.2m2 Given, a plot of dimension 45 m ×30 m.
A boundary wall of height 2.4 has to be built all round the plot at distance 1 m from the plot. Since boundary wall has to be made 1 m away from plot.
So, there will be 1 m increase in length on both sides and 1 m increase in breadth on both sides. So, new length =45+1+1=47 m New breadth =30+1+1=32 m Total area of boundary = lateral surface area of cuboid =2h(l+b)=2×2.4×(47+32)=379.2m2