A rectangle with sides 2m−1 and 2n−1 divided into squares of unit length. The number of rectangle with can be formed with sides of odd length is
A
m2n2
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B
mn(m+1)(n+1)
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C
4m+n−1
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D
None of these
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Solution
The correct option is Am2n2 There are 2m vertical and 2n horizental lines. To form the required rectangle, we must select 2 horizental lines. One even no. and one odd and one even. and similarly two vertical lines. The number of rectangle is then, mc1×mc1×nc1×nc1=m2n2.