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Question

A rectangle with sides (2n−1) and (2m−1) unit is divided into squares of length. The number of rectangle which can be formed with sides of odd length is

A
m2n2
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B
mn(m+1)(n+1)
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C
4m+n1
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D
None of these
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Solution

The correct option is A m2n2
There are 2m vertical (no:1,2,...,2m) and 2n horizontal lines.To form the required rectangle we meet select two horizontal line, one even numbered and one odd and one even and similarly 2 vartical line.The no: of rectangles is then,
mC1mC1nC1nC1=m2n2

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