A rectangular block of glass is placed on a mark made on the surface of the table and it is viewed from the vertical position of eye. If refractive index of glass be $μ$ and its thickness d, then the mark will appear to be raised up by

\frac{(μ + 1)}{μ}

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\frac{(μ - 1) d}{μ}

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\frac{(μ + 1) d}{μ d}

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\frac{(μ - 1) μ}{d}

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Solution

The correct option is D $\frac{(μ - 1) d}{μ}$
By definition $μ = a c t u a l d e p t h / A p p a r e n t d e p t h$

Let the mark be raised by a distance $x$ .
So, $μ = d / (d - x)$
On solving we get, $x = d (μ - 1) / μ$

So, B is the correct choice.

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A rectangular block of glass is placed on a mark made on the surface of the table and it is viewed from the vertical position of eye. If refractive index of glass be μ and its thickness d, then the mark will appear to be raised up by

The correct option is D (μ−1)dμBy definition μ=actual depth/Apparent depthLet the mark be raised by a distance x.So, μ=d/(d−x)On solving we get, x=d(μ−1)/μSo, B is the correct choice.

A rectangular block of glass is placed on a mark made on the surface of the table and it is viewed from the vertical position of eye. If refractive index of glass be $μ$ and its thickness d, then the mark will appear to be raised up by

The correct option is D $\frac{(μ - 1) d}{μ}$
By definition $μ = a c t u a l d e p t h / A p p a r e n t d e p t h$

Let the mark be raised by a distance $x$ .
So, $μ = d / (d - x)$
On solving we get, $x = d (μ - 1) / μ$

So, B is the correct choice.