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Question

# A rectangular channel 2 m wide carries 2.2 cumecs water in subcritical uniform flow at a depth of 1 m. What is the height of lowest transverse hump in the bottom such that critical depth is attained at the peak?

A
0.31 m
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B
0.38 m
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C
0.44 m
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D
0.49 m
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Solution

## The correct option is A 0.31 mVelocity of flow =QA=2.22=1.1m/sec E=y+V22g=1+(1.1)22×9.81=1.0617m Emin=32Yc critical depth of flow, yc=(q2g)1/3 =[(2.2/2)29.81]1/3=0.498m ∴Emin=32×0.498=0.747m Height of lowest transverse hump = E−Emin = 1.0617 - 0.747 = 0.315 m

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