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Question

A rectangular channel with bottom width 3 m, bottom slope 7×104 carries discharge of 1.80 cumecs. The depth of flow at a certain location is 0.42 m. What is the type of GVF profile? (n=0.012 and hydraulic radius is equal to depth of flow)

A
S2
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B
M3
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C
M2
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D
S1
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Solution

The correct option is C M2
Given, B=3m, S=7×104, Q=1.80 cumecs, y=0.42m

Q=Byn 1nR2/3S1/2

1.8=3yn0.012×y2/3n(7×104)1/2

yn=0.46m

Critical depth of flow, Yc=(q2g)1/3

=[(1.8/3)29.81]1/3=0.332m

Since, yn>y>yc, hence type of profile =M2

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