Question

A rectangular coil having $60$ turns and area of $0.4m^2$ is held at right angles to a uniform magnetic field of flux density $5\times {10}^{-5}$T. Calculate the magnetic flux passing through it.

Answer 1

Given : $N=60$ turns $A=0.4m^2$ $B=5\times {10}^{-5}T$
Angle between magnetic field and area vector of coil $\theta =0^o$
Thus magnetic flux passing through the coil $\varphi =NBA\cos \theta$
$\therefore$ $\varphi =60\times 5\times {10}^{-5}\times 0.4\times \cos 0^o=1.2\times {10}^{-3}Wb$