Question

A rectangular coil of $500$ turns and of area $6\times {10}^{-4}{m}^2$ is suspended inside a radial magnetic field of induction ${10}^{-4}T$ by a suspension wire of torsional constant $5\times {10}^{-10}Nm$ per degree. Calculate the current required to produce a deflection of ${10}^o$.

Answer 1

The current required to produce a deflection of ${10}^0$ is given by:

$I=\frac{C\theta }{nBA}$
$=\frac{5\times {10}^{-10}\times 10}{500\times {10}^{-4}\times 6\times {10}^{-4}}$
$=1.667\times {10}^{-4}A$ (OR)
$=0.1667mA$