Question

A rectangular conductor $LMNO$ is placed in a uniform magnetic field of $0.5T$. The field is directed perpendicular to the plane of the conductor. When the arm $MN$ of length of $20cm$ is moved towards left with a velocity of $10m{s}^{-1}$ calculate the emf induced in the arm. Given the resistance of the arm to be $5\Omega$ (assuming that other arms are of negligible resistance) find the value of the current in the arm.

Answer 1

The emf induced in the loop =$ϵ$

$ϵ=\frac{d\varphi }{dt}=\frac{d\left(Blx\right)}{dt}=Bl\frac{-dx}{dt}=Blv=0.5\times 0.2\times 10=1V$