A rectangular courtyard $5.25 m$ long and $3.78 m$ broad is to be paved exactly with square tiles measuring $0.21 m$ by $0.21 m$ . Find the number of tiles and cost of tiles if the cost of one tile is $₹ 55$ .

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Solution

Number of tiles $= \frac{a r e a o f r e c \tan g u l a r c o u r t y a r d}{a r e a o f o n e t i l e}$
$= \frac{l e n g t h \times b r e a d t h}{s i d e \times s i d e}$
$= \frac{5.25 m \times 3.78 m}{0.21 m \times 0.21 m}$
$= \frac{19.845}{0.0441}$
$= 450$ tiles
Cost of tiles $= 450 \times ₹ 55$
$= 24, 750$

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A rectangular courtyard 5.25m long and 3.78m broad is to be paved exactly with square tiles measuring 0.21m by 0.21m . Find the number of tiles and cost of tiles if the cost of one tile is ₹55.

Number of tiles =areaofrectangularcourtyardareaofonetile =length×breadthside×side =5.25m×3.78m0.21m×0.21m =19.8450.0441 =450 tilesCost of tiles =450×₹55 =24,750

A rectangular courtyard $5.25 m$ long and $3.78 m$ broad is to be paved exactly with square tiles measuring $0.21 m$ by $0.21 m$ . Find the number of tiles and cost of tiles if the cost of one tile is $₹ 55$ .