A rectangular field $242$ metres long has got an area of $4840$ $m^{2}$ . What will be the cost of fencing required to cover all the four sides, if one metre of fencing costs $5$ paise?

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Solution

Breadth of the field $= \frac{A r e a o f t h e f i e l d}{l e n g t h}$
$= (4840 \div 242) m$
$= 20 m$
$∴$ Perimeter of the field $= 2 (242 + 20) m$
$= 542 m$
cost of fencing $= R s \frac{50}{100} \times 524$
$= R s .262$

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