A rectangular field is $112 m$ long and $100 m$ wide. Two roads, each $3 m$ wide are to be constructed at the center of this field and the other is parallel to the breadth of the field.
Find the area of the two roads.

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Solution

Length of rectangular field $= 112 m$
width of rectangular field $= 100 m$
Area of $2$ roads =
$3 \times 112 + 3 \times 100 - 3 \times 3 =$
$336 + 300 - 9 = 636 - 9 = 627 m^{2}$

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A rectangular field is 112 m long and 100 m wide. Two roads, each 3 m wide are to be constructed at the center of this field and the other is parallel to the breadth of the field.Find the area of the two roads.

Length of rectangular field =112 mwidth of rectangular field =100mArea of 2 roads =3×112+3×100−3×3=336+300−9=636−9=627 m2

A rectangular field is $112 m$ long and $100 m$ wide. Two roads, each $3 m$ wide are to be constructed at the center of this field and the other is parallel to the breadth of the field.
Find the area of the two roads.

Length of rectangular field $= 112 m$
width of rectangular field $= 100 m$
Area of $2$ roads =
$3 \times 112 + 3 \times 100 - 3 \times 3 =$
$336 + 300 - 9 = 636 - 9 = 627 m^{2}$