A rectangular field is $112 m$ long and $100 m$ wide. Two roads, each $3 m$ wide are to be constructed at the center of this field and the other is parallel to the breadth of the field.
i) Find the cost of constructing the roads at $R s . 17 p e r m^{2}$

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Solution

Cost of constructing a road is $R s . 17$ per $m^{2}$ .
i.e $= 17 \times A r e a o f r o a d s$ .
$= 17 \times 627 = 10659 m^{2}$
then cost is $10659 m^{2}$

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A rectangular field is 112 m long and 100 m wide. Two roads, each 3 m wide are to be constructed at the center of this field and the other is parallel to the breadth of the field.i) Find the cost of constructing the roads at Rs. 17 per m2

Cost of constructing a road is Rs.17 per m2.i.e =17×Area of roads.=17×627=10659 m2then cost is 10659 m2

A rectangular field is $112 m$ long and $100 m$ wide. Two roads, each $3 m$ wide are to be constructed at the center of this field and the other is parallel to the breadth of the field.
i) Find the cost of constructing the roads at $R s . 17 p e r m^{2}$

Cost of constructing a road is $R s . 17$ per $m^{2}$ .
i.e $= 17 \times A r e a o f r o a d s$ .
$= 17 \times 627 = 10659 m^{2}$
then cost is $10659 m^{2}$