A rectangular field is 30 m in length and 22 m in width. Two mutually perpendicular roads, each 2.5 m wide, are drawn inside the field so that one road is parallel to the lenath of the field and the other road is parallel to its width. Calculate the area of the corssroads.

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Solution

Length of rectagular field (l)=30 m and breadth (b) =22m width of parallel roads perpendicular to each other inside the field =2.5 m

$∴$ Area of cross roads =width of roads (Length +breadth)-area of middle square

$= 2.5 (30 + 22) - (2.5)^{2}$

$= 2.5 \times 52 - 6.25 m^{2}$

=(130-6.25)m =123.75 $m^{2}$

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A rectangular field is 30 m in length and 22 m in width. Two mutually perpendicular roads, each 2.5 m wide, are drawn inside the field so that one road is parallel to the lenath of the field and the other road is parallel to its width. Calculate the area of the corssroads.

Length of rectagular field (l)=30 m and breadth (b) =22m width of parallel roads perpendicular to each other inside the field =2.5 m ∴ Area of cross roads =width of roads (Length +breadth)-area of middle square =2.5(30+22)−(2.5)2 =2.5×52−6.25m2 =(130-6.25)m =123.75 m2