Question

A rectangular field is $50\text{m×40 m}$ . Nitin takes ten rounds of its boundary . How much distance does he cover ?

Answer 1

Finding the distance covered in $10$ rounds

Length of the rectangular field $=50\text{m}$

Breadth of the rectangular field $=40\text{m}$

Nitin takes rounds of its boundary, it means we have to find the perimeter of the field .

We know that, perimeter of rectangle $=2\times (\text{length+breadth)}$

So, perimeter of the field $=2\times (50+40)$

$$\begin{gathered} =2\times 90 \\ =180\text{m} \end{gathered}$$

Distance covered by him in $1$ round $=180\text{m}$

Distance covered by him in $10$ rounds $=180\times 10=1800\text{m}$

Hence, distance covered by Nitin in $10$ rounds is $1800\text{m}$