A rectangular field is 70 m long and 60 in broad. A well of dimensions $14 m \times 8 m \times 6 m$ is dug outside the field and the earth dug-out from this well is spread evenly on the field. How much will the earth level rise?

Open in App

Solution

Length of well (l) = 14 m
Breadth (b) = 8 m
Depth (h) = 6 m
$∴$ Volume of earth dugout = $l \times b \times h$
= $14 \times 8 \times 6 = 672 m^{3}$
Length of filed = 70 m
and breadth = 60 m
Let h be the height of earth spread over
Then $70 \times 60 \times h = 672$
$\Rightarrow h = \frac{672}{70 \times 60} = 0.16$ m
$∴$ Height of earth = 0.16 m = 16 cm

Suggest Corrections

Similar questions

Q. A rectangular field is

70 m

long and

60 m

broad. A well of dimensions

14 m \times 5 m \times 6 m

is dug outside the field and the earth dugout from this well is spread evenly in the field. How much will the earth level rise?

A rectangular tank of dimensions $24 m \times 12 m \times 8 m$ is dug inside a rectangular field $600 m$ long and $200 m$ broad. The earth take out is evenly spread over the field. By how much will rise the level of the field rise?

Q. In a corner of a rectangular field with dimensions

35 m \times 22 m

, a well with 14 m inside diameter is dug 8 m deep. The earth dug out is spread evenly over the remaining part of the field. Find the rise in the level of the field. [HOTS]

Q. A field is

1700 c m

long and

11

m broad. A rectangular pit of dimensions

6 m \times 3.5 m \times 2 m

is dug anywhere in this field and dug out soil is spread evenly over the remaining part of the field. The approximate rise in the level of the rest of the field is

A field is 150 m long and 100 m wide. A plot (outside the field) 50 m long and 30 m wide is dug to a depth of 8 m and the earth taken out from the plot is spread evenly in the field. By how much is the level of field raised?

Join BYJU'S Learning Program

A rectangular field is 70 m long and 60 in broad. A well of dimensions 14m×8m×6m is dug outside the field and the earth dug-out from this well is spread evenly on the field. How much will the earth level rise?

Length of well (l) = 14 m Breadth (b) = 8 m Depth (h) = 6 m ∴ Volume of earth dugout = l×b×h = 14×8×6=672m3 Length of filed = 70 m and breadth = 60 m Let h be the height of earth spread over Then 70×60×h=672 ⇒ h=67270×60=0.16 m ∴ Height of earth = 0.16 m = 16 cm

A rectangular field is 70 m long and 60 in broad. A well of dimensions $14 m \times 8 m \times 6 m$ is dug outside the field and the earth dug-out from this well is spread evenly on the field. How much will the earth level rise?