A rectangular field is of 80 meters long and 60 meters wide. A man walked from one corner of the field to the opposite corner along the boundary of the field. Another man crossed the field diagonally to reach the opposite corner. Who walked more? How much more?

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Solution

The given rectangular field can be shown as follows.

The first man walked from corner A of the field to corner C along the boundary of the field.

∴ Path covered by the first man = (60 + 80) m = 140 m

The second man crossed the field diagonally to reach corner C from corner A.

Now, by using Pythagoras’ Theorem, we have

(AC)² = (AD)² + (DC)²

⇒ (AC)² = (60 m)² + (80 m)²

⇒ (AC)² = (3600 + 6400) m²

⇒ (AC)² = 10000 m²

⇒ AC =

⇒ AC = 100 m

∴ Path covered by the second man = 100 m

Difference between the paths covered by the men = (140 − 100) m = 40 m

Thus, the first man covered 40 m more than the second man.

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