A rectangular field is of dimension 15.4m x12.1 m. A circular well of 0.7 m radius and 3 m depth is dug in the field. The mud, dug out from the well, is spread in the field. By how much would the level of the field rise?

1 cm

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2.5 cm

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3.5 cm

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4 cm

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Solution

The correct option is B 2.5 cm
Solution: - Volume of earth taken out: $π$ r $^{2}$ h. = $π$ x (0.7) $^{2}$ x 3 = V.

Area of field without circle: (15.4x12.1)-( $π$ (0.7 $^{2}$ )) = A (say).

Axh=V

h=2.5 cm

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A rectangular field is of dimension 15.4m x12.1 m. A circular well of 0.7 m radius and 3 m depth is dug in the field. The mud, dug out from the well, is spread in the field. By how much would the level of the field rise?

The correct option is B 2.5 cmSolution: - Volume of earth taken out: πr2h. = π x (0.7)2 x 3 = V. Area of field without circle: (15.4x12.1)-(π(0.72)) = A (say). Axh=V h=2.5 cm

The correct option is B 2.5 cm
Solution: - Volume of earth taken out: $π$ r $^{2}$ h. = $π$ x (0.7) $^{2}$ x 3 = V.

Area of field without circle: (15.4x12.1)-( $π$ (0.7 $^{2}$ )) = A (say).

Axh=V

h=2.5 cm