Question

A rectangular frame of wire $abcd$ has dimensions $32cm\times 8.0cm$ and a total resistance of $2.0\Omega$. It is pulled out of a magnetic field $B=0.020T$ by applying a force of $3.2\times {10}^{-5}N$ (figure). It is found that the frame moves with constant speed. Find the emf induced in the loop.

Answer 1

In the given figure, emf induced $e$=$VBl$

If loop move with constant speed therefore electromagnetic force=external $F$.

$F=\frac{V{B}^2{l}^2}{R}=F$

$V=25m{s}^{-1}$

Now,emf $e=25\times 0.02\times 0.08$

$e=0.04V$