Question

A rectangular glass container $30$ cm by $20$ cm by $50$ cm is $\frac{4}{5}$ filled with water. Some of the water is poured into $2$ identical tins to their brims. $14$ L of water is then left in the glass container. Find the height of each tin if each has $25$ cm square base.

• A. $10$ cm
• B. $5$ cm
• C. $8$ cm
• D. $16$ cm

Answer 1

The correct option is C $8$ cm

The volume of the container

$=V=$ length $\times$ breadth $\times$ height

$=30$ cm $\times 20$ cm $\times 50$ cm

$\therefore V_{water}=30$ cm $\times 20$ cm $\times 50$ cm $\times \frac{4}{5}$

$=24000c.c$

$=24$ $l$

Water remained $=14$ $l$

So, water in the two containers $=(24-14)l=10l$.

i.e the volume of water in each container $=$$\frac{10}{2}l=5$ $l=5000c.c$.

Now area base of the small container

$=$ $25$ cm $\times 25$ cm

$\therefore$ heghit $=\frac{volume}{basearea}$

$=\frac{5000c.c}{25cm\times 25cm.}=8$ cm

So, height of the small containers $=8$ cm.