wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A rectangular hole of size 100 mm timses 50 mm is to be made on a 5 mm thick sheet of steel having ultimate tensile strength and shear strength of 500 Mpa and 300 MPa, respectively. The hole is made by a punching process. Neglecting the effect of clearance, the punching force (in kN) is

A
300
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
450
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
600
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
750
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 450


Shear area:
=P×t
=2(100+50)×5=1500mm2
Punching force:
F=τ×AS=300×1500
=450×103N=450 kN

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Force and Workdone in Punching and Blanking
PRODUCTION
Watch in App
Join BYJU'S Learning Program
CrossIcon