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Question

A rectangular hole of size 100 mm timses 50 mm is to be made on a 5 mm thick sheet of steel having ultimate tensile strength and shear strength of 500 Mpa and 300 MPa, respectively. The hole is made by a punching process. Neglecting the effect of clearance, the punching force (in kN) is

A
300
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B
450
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C
600
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D
750
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Solution

The correct option is B 450


Shear area:
=P×t
=2(100+50)×5=1500mm2
Punching force:
F=τ×AS=300×1500
=450×103N=450 kN

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