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Question

A rectangular hyperbola whose cente is C is cut by any circle of radius r in four point P, Q, R, S. The value of CP2+CQ2+CR2+CS2 is equal to :

A
r2
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B
2r2
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C
3r2
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D
4r2
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Solution

The correct option is D 4r2
Let the equation of the rectangular hyperbola be xy=c2 ...(1)
And, equation of circle be x2+y2=r2 ....(2)
Put y=c2x in equation 2, we get,
x2+c4x2=r2
x4r2x2+c4=0 .....(3)
Now, CP2+CQ2+CR2+CS2
=x12+y12+x22+y22+x32+y32+x42+y42
=2r2+2r2
=4r2

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