wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A rectangular hyperbola whose center is C, is cut by any circle of radius r in four points P, Q, R, S. Then CP2+CQ2+CR2+CS2=

A
4r2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
2r2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
r2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
8r2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 4r2
Taking the rectangular asymptotes as the axis of refernce, the equations of the hyperbola and the circle are
xy=k2 (i)x2+y2+2gx+2fy+c=0 (ii)r2=g2+f2c (iii)

Eliminating y from above equation
x4+2gx3=cx2+2fk2x+k4

Let the roots of the equations are x1,x2,x3,x4
Then,
xi=2gxixj=c

x2i=(xi)22xixjx2i=4g22c

Similarly, eliminating x
y2i=4f22c

CP2+CQ2+CR2+CS2=x21+y21+=4g22c+4f22c=4r2

flag
Suggest Corrections
thumbs-up
4
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Rectangular Hyperbola
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon