Question

A rectangular loop of area $0.06m^2$ is placed in a magnetic field 1.2 T with its plane inclined ${30}^o$ to the field direction. Find the flux linked with the plane of the loop then.

Answer 1

Flux $\varphi =\overrightarrow{B}.\overrightarrow{A}=(\overrightarrow{B}.\hat{n})A$

$⟹\varphi =BA\cos \theta$ where $\theta ={60}^o$

$⟹\varphi =1.2\times 0.06\times \frac{1}{2}$

$⟹\varphi =3.6\times {10}^{-2}weber$