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Standard XII

Physics

Motional EMF

A rectangular...

Question

A rectangular loop with a slide wire of length $l$ is kept in a uniform magnetic field as shown in figure (a). The resistance of slider is $R$ . Neglecting self inductance of the loop find the current in the connector during its motion with a velocity $v$ .

\frac{B l v}{R_{1} + R_{2} + R}

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\frac{B l v (R_{1} + R_{2})}{R (R_{1} + R_{2})}

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\frac{B l v (R_{1} + R_{2})}{R R_{1} + R R_{2} + R_{1} R_{2}}

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B l v (\frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}})

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Solution

The correct option is B $\frac{B l v (R_{1} + R_{2})}{R R_{1} + R R_{2} + R_{1} R_{2}}$
The equivalent circuit is shown in figure (c).
Obviously, $I = \frac{B l v}{R + \frac{R_{1} R_{2}}{R_{1} + R_{2}}} = \frac{B l v (R_{1} + R_{2})}{R R_{1} + R R_{2} + R_{1} R_{2}}$

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A rectangular loop with a slide wire of length l is kept in a uniform magnetic field as shown in figure (a). The resistance of slider is R. Neglecting self inductance of the loop find the current in the connector during its motion with a velocity v.

The correct option is B Blv(R1+R2)RR1+RR2+R1R2The equivalent circuit is shown in figure (c).Obviously, I=BlvR+R1R2R1+R2=Blv(R1+R2)RR1+RR2+R1R2

A rectangular loop with a slide wire of length $l$ is kept in a uniform magnetic field as shown in figure (a). The resistance of slider is $R$ . Neglecting self inductance of the loop find the current in the connector during its motion with a velocity $v$ .

The correct option is B $\frac{B l v (R_{1} + R_{2})}{R R_{1} + R R_{2} + R_{1} R_{2}}$
The equivalent circuit is shown in figure (c).
Obviously, $I = \frac{B l v}{R + \frac{R_{1} R_{2}}{R_{1} + R_{2}}} = \frac{B l v (R_{1} + R_{2})}{R R_{1} + R R_{2} + R_{1} R_{2}}$