A rectangular object of length 0.5 m is pulled by two forces, 4N along its length and other 6N making an angle of 60 degrees with the horizontal. The area of cross section of the object is 3cm2. Find the stress acting on the object
A
2.33×104N/m2
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B
2.33×10−4N/m2
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C
1.33×104N/m2
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D
1.33×10−4N/m2
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Solution
The correct option is C2.33×104N/m2 Total force acting along the length/ horizontally = 4 + 6 cos 60 = 7 N Stress acting on the object along the length or longitudinal stress = p/A=7/(3×10−4)=2.33×104N/m2 The correct option is option(a)