Question

Question 2

A rectangular piece of dimensions 3 cm x 2 cm was cut from a rectangular sheet of paper of dimensions 6 cm x 5 cm (see the figure). Area of remaining sheet of paper is


(a) $30c{m}^2$
(b) $36c{m}^2$
(c) $24c{m}^2$
(d) $22c{m}^2$

Answer 1

Given dimensions of the bigger rectangle are 6 cm and 5 cm.
$\therefore$ Area of bigger rectangle $=6cm\times 5cm=30c{m}^2$
$[\because areaofrectangle=length\times breadth]$
Also given, dimensions of the smaller rectangle are 3 cm and 2 cm.
$\therefore$ Area of smaller rectangle $=3cm\times 2cm=6c{m}^2$
$\therefore$ Area of remaining sheet of paper = Area of bigger rectangle - Area of smaller rectangle
$=(30-6)c{m}^2=24c{m}^2$