A rectangular piece of paper of length 20 cm and breadth 14 cm is folded about its breadth the curved surface area of the cylinder so formed is

180 c m^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

200 c m^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

280 c m^{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

190 c m^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $280 c m^{2}$
$2 π r = 14$
$C . S . A = 2 π r l$
$14 \times 20$
$= 280 c m^{2}$

Suggest Corrections

Similar questions

Question 48

Two cylinders A and B are formed by folding a rectangular sheet of dimensions 20 cm×10 cm along its length and also along its breadth respectively. Curved surface area of A is ___ surface area of B.

Question 48

Two cylinders A and B are formed by folding a rectangular sheet of dimensions 20 cm×10 cm along its length and also along its breadth respectively. Curved surface area of A is ___ surface area of B.

A rectangular paper is folded into a cylinder. The length and breadth of the paper are L and B respectively. The surface area of the cylinder is

___

A rectangular paper is folded into a cylinder. The length and breadth of the paper are L and B respectively. What is the outer surface area of the cylinder?

Q. A rectangular piece of paper of width 20 cm and length 44 cm is rolled along its width to form cylinder. What is the volume of the cylinder so formed?

Join BYJU'S Learning Program

A rectangular piece of paper of length 20 cm and breadth 14 cm is folded about its breadth the curved surface area of the cylinder so formed is

The correct option is C 280cm22πr=14C.S.A=2πrl14×20=280cm2

The correct option is C $280 c m^{2}$
$2 π r = 14$
$C . S . A = 2 π r l$
$14 \times 20$
$= 280 c m^{2}$