A rectangular plot is given for constructing a house having a measurement of $40 m$ length and $15 m$ in the front. According to the laws, a minimum of $3 m$ , wide space should be left in the front and back each and $2 m$ wide space on each of other sides. Find the largest area where house can be constructed.

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Solution

Largest area to built house
$= a r e a P Q R S = P Q \times Q R = (40 - 3 - 3) (15 - 2 - 2) = 34 \times 11 = 374 m^{2}$

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A rectangular plot is given for constructing a house having a measurement of 40m length and 15m in the front. According to the laws, a minimum of 3m, wide space should be left in the front and back each and 2m wide space on each of other sides. Find the largest area where house can be constructed.

Largest area to built house=areaPQRS=PQ×QR=(40−3−3)(15−2−2)=34×11=374m2

Largest area to built house
$= a r e a P Q R S = P Q \times Q R = (40 - 3 - 3) (15 - 2 - 2) = 34 \times 11 = 374 m^{2}$