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Question 4
A rectangular plot is given for constructing a house having a measurement of 40m long and 15m in the front. According to the laws, a minimum of 3m, wide place should be left in the front and back each and 2m wide space on each of other sides. Find the largest area where house can be constructed.

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Solution

Let ABCD be a rectangular plot having a measurement of 40m long and 15m in the front.

Length of inner – rectangle, EF = 40 – 3 – 3 = 34m
And breadth of inner-rectangle, FG = 15 – 2 – 2 = 11m
Another rectangle EFGH will be formed inside the rectangle ABCD
Area of inner rectangle, EFGH = Length × Breadth
=EF×FG=34×11=374m2
[ area of a rectangle = length×breadth]
Hence, the largest area where the house can be constructed in 374m2.

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