A rectangular plot of land is $50 m$ wide. The cost of fencing the plot at the rectangle $R s . 18$ per meter is $R s . 4680$ . Find
The length of the plot.

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Solution

Let the length be $x m$
Width $= 50 m$
Cost of fencing $= 4680$
Rate $= 18$
Perimeter $= \frac{4680}{18} = 260$
Perimeter $= 2 (x + 50) = 260$
$x + 50 = 130$
$\Rightarrow x = 80 m$
$∴$ Length of the plot $= 80 m$

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A rectangular plot of land is 50 m wide. The cost of fencing the plot at the rectangle Rs. 18 per meter is Rs. 4680. Find The length of the plot.

Let the length be xmWidth=50mCost of fencing=4680Rate=18Perimeter=468018=260Perimeter=2(x+50)=260x+50=130⇒x=80m∴ Length of the plot=80m

A rectangular plot of land is $50 m$ wide. The cost of fencing the plot at the rectangle $R s . 18$ per meter is $R s . 4680$ . Find
The length of the plot.

Let the length be $x m$
Width $= 50 m$
Cost of fencing $= 4680$
Rate $= 18$
Perimeter $= \frac{4680}{18} = 260$
Perimeter $= 2 (x + 50) = 260$
$x + 50 = 130$
$\Rightarrow x = 80 m$
$∴$ Length of the plot $= 80 m$