wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A rectangular sheet of the fixed perimeter with sides having their lengths in the ratio 8:15 is converted into an open rectangular box by folding after removing squares of the equal area from all four corners. If the total area of removed squares is 100, the resulting box has maximum volume. The lengths of the sides of the rectangular sheet are


A

24

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

32

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

45

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

60

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

45


Explanation for the correct option:

Step 1. Find the length of the side of rectangular sheet:

Let the side of the square be x.

Volume =(15k2x)(8k2x)x

=f(x)

Now, 4×x2=100

x2=25

x=5

dVdxx=0=6x246kx+60k2

Step 2. f'(x)=dVdxx=0

6x246kx+60k2=0

6×(5)246k(5)+60k2=0

1523k+6k2=0

6k223k+15=0

k=3,56

Side of the rectangle =15k,8k

=15×3,8×3

=45,24

Hence, Option ‘A’ and ‘C’ is Correct.


flag
Suggest Corrections
thumbs-up
13
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Total Surface Area of a Cuboid
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon