A rectangular sheet of tin foil of size 30 cm - 18 cm can be rolled to form a cylinder - radius of the cylinder thus formed is -

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Standard VII

Physics

Volume of Regular Solids

A rectangular...

Question

A rectangular sheet of tin foil of size $30 c m \times 18 c m$ can be rolled to form a cylinder , radius of the cylinder thus formed is ?

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Solution

$A r e a o f r e c t a n g u l a r s h e e t = 30 \times 18$

$= 540 c m^{2}$

$h e r e, l = 30 c m$

$C u r v e d s u r f a c e a r e a o f c y l i n d e r = a r e a o f r e c t a n g u l a r s h e e t$

$∴ 2 π r l = 540$

$∴ r = \frac{540}{2 \times π \times 30}$

$r = \frac{9}{π} c m$

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A rectangular sheet of tin foil of size 30 cm ×18 cm can be rolled to form a cylinder , radius of the cylinder thus formed is ?

Area of rectangular sheet =30×18 =540 cm2here,l=30cmCurved surface area of cylinder =area of rectangular sheet∴2πrl= 540∴r=5402×π×30r=9πcm

A rectangular sheet of tin foil of size $30 c m \times 18 c m$ can be rolled to form a cylinder , radius of the cylinder thus formed is ?

$A r e a o f r e c t a n g u l a r s h e e t = 30 \times 18$

$= 540 c m^{2}$

$h e r e, l = 30 c m$

$C u r v e d s u r f a c e a r e a o f c y l i n d e r = a r e a o f r e c t a n g u l a r s h e e t$

$∴ 2 π r l = 540$

$∴ r = \frac{540}{2 \times π \times 30}$

$r = \frac{9}{π} c m$