A rectangular tank $15 m$ long and $11 m$ broad is required to receive entire liquid contents into a cylindrical tank of internal diameter $21 m$ and length $5 m$ . Find the least height of the tank that will serve the purpose.

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Solution

$15 \times 11 \times h = π {(\frac{21}{2})}^{2} \times 5$

$\Rightarrow h = 10.49 m$

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A rectangular tank 15m long and 11m broad is required to receive entire liquid contents into a cylindrical tank of internal diameter 21m and length 5m. Find the least height of the tank that will serve the purpose.

15×11×h=π(212)2×5⇒h=10.49m

A rectangular tank $15 m$ long and $11 m$ broad is required to receive entire liquid contents into a cylindrical tank of internal diameter $21 m$ and length $5 m$ . Find the least height of the tank that will serve the purpose.

$15 \times 11 \times h = π {(\frac{21}{2})}^{2} \times 5$

$\Rightarrow h = 10.49 m$