Question

A rectangular tank of base area $100m^2$ has a height of $2m$. Calculate the thrust at the bottom of the tank, if it is filled upto the brim with water of density ${10}^{3}kg{m}^{-3}$.

Answer 1

Given that,

density of water $\left(\rho \right)={10}^{3}Kg/m^3$

water fixed up till height $\left(h\right)=2m$

Area of base $\left(A\right)=100m^2$.

assuming atmospheric pressure $\left(P_0\right)=1atm\simeq {10}^{5}Pa$

so, pressure at bottom of tank,

$P=P_0+\rho gh$.

$={10}^5+{10}^3\times 10\times 2[g=10m/s^2]$

$P=(1.2\times {10}^5)Pa$

Thus, thrust on bottom surface,

$F=P.A=(1.2\times {10}^5)\times {10}^2\Rightarrow F=1.2\times {10}^{7}N$