A rectangular tank of depth $8$ meter is full of water $n = 4 / 3$ , the bottom is seen at the depth:

$6 c m$

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$8 / 3 c m$

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$8 c m$

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$10 c m$

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Solution

The correct option is A
$6 c m$

Given refractive index, $n = \frac{4}{3}$
Real depth $= 8 c m$
$n = \frac{R e a l d e p t h}{A p p a r e n t d e p t h}$

$\frac{4}{3} = \frac{8}{A p p a r e n t d e p t h}$

Apparent depth $= 6 c m$

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If a rectangular tank of depth 8 metre is full of water $μ = \frac{4}{3}$ , then the bottom is seen at a depth of___metres.

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8

μ = \frac{4}{3}

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