A rectangular water reservoir contains 105 m^3 of water. Find the depth of t the reservoir if its base measures 12 m by 3.5 m.

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Solution

Volume of the water in reservoir = 105 m^3
Length (l) = 12 m
and breadth (b) = 3.5
Depth (Height) of water = $\frac{V o l u m e}{l \times b}$
= $\frac{105}{12 \times 3.5} m = \frac{105}{45} = \frac{5}{2} m = 2.5 m$

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A rectangular water reservoir contains 105 m^3 of water. Find the depth of t the reservoir if its base measures 12 m by 3.5 m.

Volume of the water in reservoir = 105 m^3 Length (l) = 12 m and breadth (b) = 3.5 Depth (Height) of water = Volumel×b =10512×3.5m=10545=52m=2.5 m

Volume of the water in reservoir = 105 m^3
Length (l) = 12 m
and breadth (b) = 3.5
Depth (Height) of water = $\frac{V o l u m e}{l \times b}$
= $\frac{105}{12 \times 3.5} m = \frac{105}{45} = \frac{5}{2} m = 2.5 m$