A rectangular water reservoir contains $42000 m$ of water. Find the depth of water in the reserve if its base measures $6 m \times 3.5 m$

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Solution

$\begin{matrix} G i v e n l e n g t h o f t h e r e c tan g u l a r r e s e r v o i r = 6 m B r e a d t h = 3.5 m L e t t h e d e p t h o f t h e c u b o i d b e h G i v e n v o l u m e = 42000 l i t e r = 42 m^{3} w e k n o w t h a t t h e v o l u m e o f a c u b o i d = l \times b \times h \Rightarrow 6 m \times 3.5 m \times h m = 42 m^{3} \Rightarrow 21 h m^{3} = 42 m^{3} \Rightarrow h = \frac{42 m^{3}}{21 m^{3}} ∴ h = 2 m ∴ t h e d e p t h o f t h e r e s e r v o i r i s 2 m . \end{matrix}$

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A rectangular water reservoir contains 42000m of water. Find the depth of water in the reserve if its base measures 6m×3.5m

Givenlengthoftherectangularreservoir=6mBreadth=3.5mLetthedepthofthecuboidbehGivenvolume=42000liter=42m3weknowthatthevolumeofacuboid=l×b×h⇒6m×3.5m×hm=42m3⇒21hm3=42m3⇒h=42m321m3∴h=2m∴thedepthofthereservoiris2m.

A rectangular water reservoir contains $42000 m$ of water. Find the depth of water in the reserve if its base measures $6 m \times 3.5 m$