A rectangular water reservoir is 15 m by 12 m at the base. Water flows into it through a pipe whose cross-section is 5 cm by 3 cm at the rate of 16 m per second. Find the height to which the water will rise in the reservoir in 25 minutes:

0.2 m

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2 cm

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0.5 m

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None of these

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Solution

The correct option is A 0.2 m
Volume of water which flow in 25 minutes $= 25 \times 60 \times 0.05 \times 0.03 \times 16 = 36 m^{2}$
$∴$ Rise in water level $= \frac{36}{15 \times 12} = \frac{1}{5} m = 0.2 m$

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A rectangular water reservoir is 15 m by 12 m at the base. Water flows into it through a pipe whose cross-section is 5 cm by 3 cm at the rate of 16 m per second. Find the height to which the water will rise in the reservoir in 25 minutes:

The correct option is A 0.2 mVolume of water which flow in 25 minutes =25×60×0.05×0.03×16=36m2 ∴ Rise in water level =3615×12=15m=0.2m

The correct option is A 0.2 m
Volume of water which flow in 25 minutes $= 25 \times 60 \times 0.05 \times 0.03 \times 16 = 36 m^{2}$
$∴$ Rise in water level $= \frac{36}{15 \times 12} = \frac{1}{5} m = 0.2 m$