CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

A rectangular wire-loop of width a is suspended from the insulated pan of a spring balance as shown in figure (34 - E5). A current i exists in the anticlock wise direction in the loop. A magnetic field B exists in the lower region. Find the change in the tension of the spring if the current in the loop is reversed.

Open in App
Solution

Force in the lower side of rectingular loop due to current i in magnetic field B Initially when current is flowing in anticlockwise direction

Then F = iaB in right of a.

When current is reversed the rension is

F = iaB in left a

So, change in tension

= iaB - (- iaB) = 2 iaB.


flag
Suggest Corrections
thumbs-up
4
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Force on a Current Carrying Wire
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon