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Question

A rectangular wire-loop of width a is suspended from the insulated pan of a spring balance as shown in figure (34 - E5). A current i exists in the anticlock wise direction in the loop. A magnetic field B exists in the lower region. Find the change in the tension of the spring if the current in the loop is reversed.

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Solution

Force in the lower side of rectingular loop due to current i in magnetic field B Initially when current is flowing in anticlockwise direction

Then F = iaB in right of a.

When current is reversed the rension is

F = iaB in left a

So, change in tension

= iaB - (- iaB) = 2 iaB.


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