A red-brown metal X forms a salt $X S O_{4}$ . When hydrogen sulphide gas is passed through an aqueous solution of $X S O_{4}$ , then a black precipitate of XS is formed alongwith sulphuric acid solution.

(a) What could the salt $X S O_{4}$ be ?

(b) What is the colous of salt $X S O_{4}$ ?

(c) Name the black precipitate XS.

(d) By using the formula of the salt obtained in (a) above, write an equation of the reaction which takes place when hydrogen sulphide gas is passed through its aqueous solution.

(e) What type of chemical reacion takes place in this case ?

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Solution

(a) Copper sulphate.
(b) Blue colour.
(c) Copper sulphide.
(d) $C u S O_{4} (a q) + H_{2} S (g) ⟶ C u S (s) + H_{2} S O_{4} (a q)$
(e) Double displacement reaction.

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(a) Copper sulphate. (b) Blue colour. (c) Copper sulphide. (d)CuSO4(aq)+H2S(g)⟶CuS(s)+H2SO4(aq) (e) Double displacement reaction.

(a) Copper sulphate.
(b) Blue colour.
(c) Copper sulphide.
(d) $C u S O_{4} (a q) + H_{2} S (g) ⟶ C u S (s) + H_{2} S O_{4} (a q)$
(e) Double displacement reaction.