A red solid is insoluble in water, but soluble in the presence of $K I$ . Heating the red solid in a test tube result in the formation of yellow sublimate in the test tube. The red solid is :

P b_{3} O_{4}

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H g I_{2}

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H g O

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(N H_{4})_{2} C r_{2} O_{7}

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Solution

The correct option is B $H g I_{2}$

Reaction:
$H g I_{2} + 2 I^{-} \to [H g I_{4}]^{2 -}$ (Soluble)
Red solid is $H g I_{2}$ , it dissolves in excess of KI due to the formation of complex.

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The solubility of

H g I_{2}

in water decreases in presence of

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Reason:

H g I_{2}

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A red solid is insoluble in water, but soluble in the presence of KI. Heating the red solid in a test tube result in the formation of yellow sublimate in the test tube. The red solid is :

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A red solid is insoluble in water, but soluble in the presence of $K I$ . Heating the red solid in a test tube result in the formation of yellow sublimate in the test tube. The red solid is :

The correct option is B $H g I_{2}$

Reaction:
$H g I_{2} + 2 I^{-} \to [H g I_{4}]^{2 -}$ (Soluble)
Red solid is $H g I_{2}$ , it dissolves in excess of KI due to the formation of complex.