A refrigerating machine working on reversed carnot cycle takes out 2 kW per minute of heat from the system while between temperature limits of 300 K and 200K. COP and power consumed by the cycle will be respectively.

1 and 1kW

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2 and 1 kW

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1 and 2 kW

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2 and 2 kW

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Solution

The correct option is B 2 and 1 kW
Given data :
$Q_{2} = 2 k W$
$T_{1} = 300 K$
$T_{2} = 200 K$
$C O P = \frac{T_{2}}{T_{1} - T_{2}}$
$= \frac{200}{300 - 200} = 2$
also $C O P = \frac{Q_{2}}{W}$
$∴ 2 = \frac{2}{W}$
or $W = \frac{2}{2} = 1 k W$ per minute

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A refrigerating machine working on reversed carnot cycle takes out 2 kW per minute of heat from the system while between temperature limits of 300 K and 200K. COP and power consumed by the cycle will be respectively.

The correct option is B 2 and 1 kWGiven data : Q2=2kW T1=300K T2=200K COP=T2T1−T2 =200300−200=2 also COP=Q2W ∴2=2W or W=22=1kW per minute

The correct option is B 2 and 1 kW
Given data :
$Q_{2} = 2 k W$
$T_{1} = 300 K$
$T_{2} = 200 K$
$C O P = \frac{T_{2}}{T_{1} - T_{2}}$
$= \frac{200}{300 - 200} = 2$
also $C O P = \frac{Q_{2}}{W}$
$∴ 2 = \frac{2}{W}$
or $W = \frac{2}{2} = 1 k W$ per minute