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Question

A refrigerator absorbs 2000 cals of heat from ice trays. If the coefficient of performance is 4, then work done by the motor is

A

2100 J

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B

4200 J

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C

8400 J

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D

500 J

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Solution

The correct option is A 2100 J
$Q_{2} = 2000 c a l$
COP $= \frac{Q_{2}}{W}$
Therefore $4 = \frac{2000}{W}$
$W = 500 c a l = 500 \times 4.2 = 2100 J$

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