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Heat Transfer

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Question

A refrigerator absorbs $2500$ calories of heat from ice trays. If the coefficient of performance is $5$ , the work done by motor is:

A

2000 J

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B

4000 J

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C

2100 J

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D

1500 J

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Solution

The correct option is C $2100 J$
A refrigerator absorbs $2500 c a l o r i e s = 4.2 * 2500 = 10, 500 J$ of heat from ice trays. If the coefficient of performance is 5,

$C O P = \frac{h e a t}{w o r k}$

$H e a t = \frac{h e a t}{C O P} = \frac{10500}{5} = 2, 100 J$

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