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Calorific Value and Efficiency of a Fuel

Arefrigerator...

Question

A refrigerator works between 4 C and 30 C. It is required to remove 600 of calories heat every second in order to keep temperature of the refrigerated space constant. The power required is (take 1 cal.=4.2 joule)

A

2.365 w a t t

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B

2365 w a t t

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C

236.5 w a t t

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D

23.65 w a t t

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Solution

The correct option is D $236.5 w a t t$
The required power is 236.5 W
Given:
Temperature of the source, = 30 C = 30 + 273 = 303 K
Temperature of sink, = 4 C = 4 + 273 = 277 K
To find:
Power required for the given condition

Solution:
We Know,
Where, Q2 is the heat drawn out from the sink at T2
W is the work done on the working substance,
Q1 is the heat rejected to source at room temperature T1.
That is,
W = 236.5 J
Power
=236.5 J

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