A regular copolymer of ethylene and vinyl chloride contains alternate monomers of each type. What is the mass percentage of ethylene in this co-polymer?

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Solution

The structure of the co-polymer is
$n C H_{2} = C H_{2} + n C H_{2} = C H C l \to (C H_{2} C H_{2} C H_{2} C H C l)_{n}$
Mol. mass of ethylene=28 g
Mol. mass of vinyl chloride=62.5 g
Empirical formula mass of the co-polymer = $28 + 62.5 = 90.5$ g
So, the mass percentage of ethylene in this co-polymer=
$\frac{28}{90.5} \times 100 = 30.94 %$

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